A steam engine piston of mass 30 kg is at rest if after 0.2 second it attains a velocity of 3.5 meters per second what is the average acceleration force acting on it during 0.25 second
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Average acceleration=Change in velocity ÷Eclapsed time.
So,the velocity is 3.5 and time is 0.25.
Average acceleration=3.5/0.25=14 ms inverse 2.
So,the velocity is 3.5 and time is 0.25.
Average acceleration=3.5/0.25=14 ms inverse 2.
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