A steam engine takes in 4.5 x 105J of energy added as heat and exhausts2.0 x 10 5J of energy removed as heat per cycle. What is its % efficiency and work done?
Answers
Given :
Heat gained = 4.5 × 10⁵ J
Heat released = 2 × 10⁵ J
To Find :
Percentage efficiency of steam engine and work done per cycle..
Solution :
❒ Efficiency of a heat engine/steam engine is given by, η = 1 - (Q₂ / Q₁)
Where,
η denotes efficiency
Q₂ denotes heat released to the sink
Q₁ denotes heat extracted from the source
By substituting the given values;
➛ η = 1 - (Q₂ / Q₁)
➛ η = 1 - (2 × 10⁵ / 4.5 × 10⁵)
➛ η = 1 - 0.44
➛ η = 0.56
Percentage efficiency = 56%
❒ Work done per cycle :
We know that work done is measured as the change in energy.
➠ W = Q₁ - Q₂
➠ W = (4.5 × 10⁵) - (2 × 10⁵)
➠ W = 2.5 × 10⁵ J
hope this help uh :)
Answer:
Solution:
Given
Principal (p) = Rs50000
Rate of interest (r) = 8% p.a
Let the amount at the end of the second year = A
\boxed{Amount = p\times(1+\frac{r}{100})^{n}}
Amount=p×(1+
100
r
)
n
i)
Let the number of times interest paid in 2 years ( n)=2
A = 50000[1+8/100]²
= 50000 × (108/100)²
= 5×108×108
= Rs58320
Therefore,
The amount standing to her
credit at the end of the second
year (A) = Rs58320
ii ) Finding interest for third year:
P = Rs 58320,
R = 8%
T = 1 year
Simple Interest (I) = (PTR)/100
= ( 58320 × 1 × 8 )/100
= Rs 4665.60
••••
Explanation:
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