A steamer goes downstream and covers the distance between two ports in 4hrs while it covers the same distance upstream in 6 hrs. if the speed of stream is 2km/h, find the speed of the streamer in still water
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Let the speed of the steamer in still water be x km/h.
Then, the speed downstream =(x+2) km/h
and the speed upstream =(x−2) km/h
Given, distance covered in 4 hours downstream = distance covered in 5 hours upstream
∴4(x+2)=5(x−2)
⇒4x+8=5x−10
⟹4x−5x=−10−8
[Transposing 5x to LHS and 8 to RHS]
⟹−x=−18 or x=18km/h
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