Question

A steamer goes downstream and covers the distance between two point in 4 hours while it covers the same distance upstream in 6 hours if the speed of stream into km per hour find the speed of Seema is in still water



Answer : Let speed of steamer in still water =
$x km \hour$
The speed of steamer in down stream =
$(x + 2) km \hour$

Distance =
$speed \times time$
Distance covered in
$6 \: hour$
while going downstream
Distance =
$(x + 2) \times 4$
Distance =
$(x - 2) \times 6$
distance =
$6 (x + 2)km$
Since the distance in both cases are same therefore.

$4(x + 2) = 6(x - 2)$
$4x + 8 = - 12 - 8$
$- 2x = - 20$
$2x = 20$
reduced the
$20 \div 2$
the answer is
$10km \: per \: hour$






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Answer 1

Answer:

A steamer goes downstream and covers the distance between two point in 4 hours while it covers the same distance upstream in 6 hours if the speed of stream into km per hour find the speed of Seema is in still water

Step-by-step explanation:

Answer : Let speed of steamer in still water =

$x km \hour$

The speed of steamer in down stream =

$(x + 2) km \hour$

Distance =

$speed \times time$

Distance covered in

$6 \: hour$

while going downstream

Distance =

$(x + 2) \times 4$

Distance =

$(x - 2) \times 6$

distance =

$6 (x + 2)km$

Since the distance in both cases are same therefore.

$4(x + 2) = 6(x - 2)$

$4x + 8 = - 12 - 8$

$- 2x = - 20$

$2x = 20$

reduced the

$20 \div 2$

the answer is

$10km \: per \: hour$

Answer 2

Step-by-step explanation:

=

$speed \times time$

Distance covered in

$6 \: hour$

while going downstream

Distance =

$(x + 2) \times 4$

Distance =

$(x - 2) \times 6$

distance =

$6 (x + 2)km$

Since the distance in both cases are same therefore.

$4(x + 2) = 6(x - 2)$

$4x + 8 = - 12 - 8$

$- 2x = - 20$

$2x = 20$

reduced the

$20 \div 2$

the answer is

$10km \: per \: hour$