Question

a steel ball initially at a pressure of 1.0 into 10 power 5 Pascal is heated from 20 degree Celsius to 120 degree Celsius keeping its volume constant.find the pressur inside the steel ball​

Answer 1

Answer:

A steel ball initially at a pressure of 1.0 into 10 power 5 Pascal is heated from 20 degree Celsius to 120 degree Celsius keeping its volume constant.

Explanation:

According to the definition of Bulk Modulus,

B=−P/ΔV/V

⇒ P=−B(ΔV/V)

According to the thermal expansion,

V'=V(1+3αΔT)

⇒ ΔV=V'−V

       =V3αΔT

⇒ ΔV/V=3αΔT

Thus,

P=B(3αΔT);

P = 3×1.6×10^11×12×10^(−6)×(120−20)

 P =576×10^6

P = 5.76×10^8 N/m^2 or 5.76×10^8 pascal