a steel ball initially at a pressure of 10^5 Pa is heated from 30°c to 130°c keeping its volume constant the final pressure inside the ball is
please say the answer
Answers
Answered by
1
Answer:
ANSWER
The ball tries to expand its volume. But it is kept in the same volume. So it is kept at a constant volume.
So the stress arises is defined as:
(
V
ΔV
)
P
=B
⇒P=B
V
ΔV
=B×γΔθ
Substiting the values in above relation:
P=B×3αΔθ
=1.6×10
11
×10
−6
×3×12×10
−6
×(120−20)
=57.6×19
7
≈5.8×10
8
pa
Similar questions