A steel ball is released from rest in a container of oil .its downward acceleration a=2,4-.6v , what is ball s downward velocity 2s after it is released
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Explanation:
We are given
a = -2 m/s² (problem says the acceleration is downward, hence negative)
t = 2 s
u = 0 ( because problem says the ball is released from rest, which implies it was not moving initially)
By first kinematic equation of motion-
v = u + at
(Putting the values)
v = 0 + ( -2 x 2)
→ v = -4 m/s
Therefore, the ball will accelerate to
4 m/s downwards after 2 seconds
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