Question

A steel ball of 3 mm radius is falling in glycrine .find the terminal velocity of the ball .take (g=10m/s²)
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Answer 1

Answer:

d=2mm

=2×10

−3

m

r=10

−3

m

η=8.3 poise=8.3×

10

1

deca poise =0.83

g=9.8

s=10

3

×8kg

6g=1.3×10

3

kg/m

3

θ

t

=

9η

2r

2

(s−6g)g

=

9×0.83

2×10

−3

×10

−3

×9.8×8×10

3

−1.3×10

3

=

242

19.6×10

−6

×10

3

×6.7×10

2

=0.17×10

−1

θ

t

=1.7×10

−2

m/s.

see this properly and do it by your own all the best.