Question

a steel ball of mass 1 kg and specific heat 0.4 kj/kg is at a temperature of 60 deg c. it is dropped into 1 kg of water at 20 deg c. the final steady temperature of water is

Answer 1

Mass of ball = 1kg ( Given)

Specific heat = 0.4kg ( Given)

Temperature = 60°C

The problem follows the method of simple conservation of energy.. ie heat lost equal heat gain..

Thus,

Heat lost by hot body(Ball) =Heat gained by cold body(water)

mCb(th-tf) = mw(tf-th)             [Cw=4.1]

=  tf =23.5 degreeC.

Answer 2

Answer:

A steel ball of mass 1 kg of specific heat 0.4 kj/ kgk is at temperature of 60o

Liquid water has one of the highest specific heats among common substances, about 4182 J/(K kg) at 20 °C; but that of ice just below 0 °C is only 2093 J/(K kg).Liquid water has one of the highest specific heats among common substances, about 4182 J/(K kg) at 20 °C; but that of ice just below 0 °C is only 2093 J/(K kg).The "X" comes from the Greek letter Chi, which is the first letter of the

c. It is dropped into 1 kg water at 20o

c. The final steady state temperature of water is