Question

A steel ball of mass 5g is thrown downwards with velocity 10m/s from the height 19.5m it penetrates sand by 50cm the change in mechanical energy will be

Answer 1

For explanation see the attachment file

Answer 2

Given that,

Mass of the steel ball, m = 5 g = 0.005 kg

Velocity of the ball, v = 10 m/s

From the height 19.5 m it penetrates sand by 50 cm.

To find,

We need to find the change in its mechanical energy.

Solution,

Kinetic energy of the ball is :

$K=\dfrac{1}{2}mv^2=\dfrac{1}{2}\times 0.005\times (10)^2=0.25\ J$

Potential energy from the height 19.5 m it penetrates sand by 50 cm is given by :

$P=mgh=0.005\times 10\times (19.5+0.5)=1\ J$

Total mechanical energy of the stone is given by :

M = 0.25 + 1

M = 1.25 J

So, the change in mechanical energy will be 1.25 J.

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Mechanical energy

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