Science, asked by lakshith69, 7 months ago

A steel bar 2 m long and 150 mm2 in cross-section is subjected to an axial pull of 15kN. Find the elongation of the bar. Take E = 200 GPa.​

Answers

Answered by brainlya2
1

Answer:

Hi frnd hope my answer helps

Explanation:

A steel rod 1 m long and 20 mm x 20 mm in cross-sectional is subjected to a tensile force of 40 kN. Determine the elongation of the road, if modulus of elasticity for the rod material is 200 GPa.

Give:

b = 20 mm

h = 20 mm

L = 1 m = 1 000 mm

F = 20 kN = 40 000 N

E = 200 GPa = 200 000 MPa

Req.:

DL = ?

Solution:

σ = F / A

A = b x h = 20 x 20 = 400 mm2

σ = F/A = 40 000/400 = 100 MPa

E = σ / e

e = DL / L

E = σ /(DL / L) = σ L / DL

200 000 = 100 x 1 000 / DL

DL = 100 x 1 000 / 200 000 = 0.5 mm (Ans.)

DL = 0.5 mm

Answered by ahireharshal2002
3

Answer:

1.om

Explanation:

find elongation of the bar

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