A steel bar 2 m long and 150 mm2 in cross-section is subjected to an axial pull of 15kN. Find the elongation of the bar. Take E = 200 GPa.
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1
Answer:
Hi frnd hope my answer helps
Explanation:
A steel rod 1 m long and 20 mm x 20 mm in cross-sectional is subjected to a tensile force of 40 kN. Determine the elongation of the road, if modulus of elasticity for the rod material is 200 GPa.
Give:
b = 20 mm
h = 20 mm
L = 1 m = 1 000 mm
F = 20 kN = 40 000 N
E = 200 GPa = 200 000 MPa
Req.:
DL = ?
Solution:
σ = F / A
A = b x h = 20 x 20 = 400 mm2
σ = F/A = 40 000/400 = 100 MPa
E = σ / e
e = DL / L
E = σ /(DL / L) = σ L / DL
200 000 = 100 x 1 000 / DL
DL = 100 x 1 000 / 200 000 = 0.5 mm (Ans.)
DL = 0.5 mm
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3
Answer:
1.om
Explanation:
find elongation of the bar
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