Question

A steel bar having cross sectional area of 100 П mm2 is subjected to a tensile force of 40 KN determine the tensile stress

Answer 1

Explanation:

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Answer 2

The tensile stress acting on a steel bar is $1.27\times 10^8\ Pa$.

Explanation:

We are given that,

Tensile force acting on the steel bar, F = 40 kN

Area of cross section of the steel bar, $A=100\pi mm^2=100\pi \times 10^{-6}\ m^2$

It is required to find the tensile stress. It is given by :

$P=\dfrac{F}{A}\\\\P=\dfrac{40\times 10^3}{100\pi \times 10^{-6}}\\\\P=1.27\times 10^8\ Pa$

So, the tensile stress acting on a steel bar is $1.27\times 10^8\ Pa$.

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