Question

A steel Bartan (vessels) company's 90℅ product are of good quality . Ravi went to market to purchase 5 Bartan
on Dhanteras . What is the probability that he will never buy product of that company again ?
[ If won't buy if more then 2 vessels are of low quality ]

Don't spam & Happy Dhanteras​

Answer 1

Step-by-step explanation:

If total bartan(vessels) are 100

Good quality ----------> 90

Bad quality ------------> 10

Condition=>

[If won't buy if more then 2 vessels are of low quality]

He wants to buy 5 vessels

Probability of getting good vessels are

$\frac{n(a)}{n(s)} = \frac{5}{90} = \frac{1}{18} = 0.055$

Probability of getting bad quality vessels are

$\frac{n(a)}{n(s)} = \frac{5}{10} = 0.5$

he will never buy product of that company again if 2 vessels are bad

Probability of it is

$\frac{n(a)}{n(s)} = \frac{2}{10} = \frac{1}{5} = 0.2$

$there \: is \: 0.2 \: possibility \: that \: his \: vessel \: \\ will \: be \: of \: bad \: quality..... \\ \\ \\ please \: report \: the \: answer \: sir \: \\ if \: it \: is \: incorrect$

Answer 2

${\bold{\underline{\boxed{SoluTion:}}}}$

Let the total number of Vessels = 100

vessels with good quality = 90

vessels with bad quality = 100 - 90 = 10

$\implies$ Ravi won't buy if more then 2 vessels are of low quality.

Now, According to the question

Ravi wants to buy 5 vessels

$\implies$ $\therefore$ Probability of getting good vessels are

= $\frac{Number\:of\:good\:vessels}{Total\:number\:of\:good\:vessels}$

⇒ $\sf\dfrac{5}{90} =\sf\cancel\dfrac{1}{18}=0.055$

Probability of getting bad vessels

= $\frac{Number\:of\:bad\:vessels}{Total\:number\:of\:bad\:vessels}$

⇒$\frac{5}{10}=\sf\cancel\dfrac{1}{2}=0.5$

Probability of never buy vessel of low

quality is 2

$\therefore$ $\frac{2}{10}=\sf\cancel\dfrac{1}{2} = \sf0.2$