Question

a steel bullet is making 180 revolutions per minute, under a constant torque of 5 N-m. if it drills a hole in 7s in a steel block of mass of 600gm. rise in temperature of the block.( s=0.1 cal/gm/°C)
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Answer 1

Answer:

Work done by the couple in 7 second =τ∗θ=5∗2π∗3∗7

This will make a rise in temp = msT= 210 π

S= 0.1/4.2 J/g/K

t comes 46K or degree celcius as it's only change in temp