A steel cable with a radius of 1.5 cm supports a chairlift at a ski area. If the maximum stress is not to exceed 108 N m–2, what is the maximum load the cable can support?
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68
Given,
radius of steel cable (r) = 1.5cm = 1.5 × 10^-2 m
Cross section area of steel cable ( A) = πr² = 3.14 × (1.5×10^-2)² m²
= 3.14 × 2.25 × 10^-4 m²
= 7.065 × 10^-4 m²
maximum stress = 10^8 N/m²
We know,
Maximum Force ( load ) = cross section area × maximum stress
= 10^8 × 7.065 × 10^-4
= 7.065 × 10⁴ N
radius of steel cable (r) = 1.5cm = 1.5 × 10^-2 m
Cross section area of steel cable ( A) = πr² = 3.14 × (1.5×10^-2)² m²
= 3.14 × 2.25 × 10^-4 m²
= 7.065 × 10^-4 m²
maximum stress = 10^8 N/m²
We know,
Maximum Force ( load ) = cross section area × maximum stress
= 10^8 × 7.065 × 10^-4
= 7.065 × 10⁴ N
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13
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