A steel cable with a radius of 1.5 cm supports a chairlift at a ski area. If the maximum stress is not to exceed 10⁸ N m⁻², what is the maximum load the cable can support?
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Answered by
8
given,
radius of steel cable , R = 1.5cm or 0.015m
maximum stress is not to exceeded 10^8 N/m²
so, maximum stress = 10^8 N/m²
we know, stress = applied force/cross section area.
so, maximum stress = maximum force or load/cross section area
or, maximum load can support the cable = maximum stress × cross sectional area.
cross sectional area = πr² = π(0.015)² m²
so, maximum load can support on the cable = 10^8 × π(0.015)²
= 7.065× 10⁴ N
radius of steel cable , R = 1.5cm or 0.015m
maximum stress is not to exceeded 10^8 N/m²
so, maximum stress = 10^8 N/m²
we know, stress = applied force/cross section area.
so, maximum stress = maximum force or load/cross section area
or, maximum load can support the cable = maximum stress × cross sectional area.
cross sectional area = πr² = π(0.015)² m²
so, maximum load can support on the cable = 10^8 × π(0.015)²
= 7.065× 10⁴ N
Answered by
15
Answer:
Explanation:
given,
radius of steel cable , R = 1.5cm or 0.015m
maximum stress is not to exceeded 10^8 N/m²
so, maximum stress = 10^8 N/m²
we know, stress = applied force/cross section area.
so, maximum stress = maximum force or load/cross section area
or, maximum load can support the cable = maximum stress × cross sectional area.
cross sectional area = πr² = π(0.015)² m²
so, maximum load can support on the cable = 10^8 × π(0.015)²
= 7.065× 10⁴ N
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