a steel cable with radius of 1.5cm supports a chairlift at a sky area. If the maximum stress is not exceed 10^8 N/m2 then what is the max. load the cable can support
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Answered by
4
Radius of the steel cable, r = 1.5 cm = 0.015 m
Maximum allowable stress = 108 N m–2
Maximum stress = Maximum force / Area of cross-section
∴ Maximum force = Maximum stress × Area of cross-section
= 108 × π (0.015)2
= 7.065 × 104 N
Hence, the cable can support the maximum load of 7.065 × 104 N.
Maximum allowable stress = 108 N m–2
Maximum stress = Maximum force / Area of cross-section
∴ Maximum force = Maximum stress × Area of cross-section
= 108 × π (0.015)2
= 7.065 × 104 N
Hence, the cable can support the maximum load of 7.065 × 104 N.
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Answered by
5
Solution-
Load = stress × area
10^8 × π^2
10^8 × 3.14 ( 1.5 × 10^-2)
7.07 × 10^4N
Load = stress × area
10^8 × π^2
10^8 × 3.14 ( 1.5 × 10^-2)
7.07 × 10^4N
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