Question

A steel cube 0.32cm each side suspended by a scale and immersed in water. What scale reads

Answer 1

Given
One side of cube = 0.32 cm

Then volume of cube = (side)^3
= (0.32)^3
= 0.032768 cm^3

now as force exerted by water on cube
= volume of water displaced × density of water × g

And as cube is immersed then
volume of water displaced= volume of cube

=> F(by water on cube) = 0.032768 cm^3 ×( 1gram/cm^3)× g
= 0.032768 gram ×g

and now

force (by earth on cube ) ( density of steel = 8.05 gram per cm^3)
= volume ×dencity × g
= 0.032768 × 8.05 × g
= 0.264 gram × g

now resulting force

= (0.264 - 0.033 ) gram × g
= 0.231 gram × g

= 2.31 Newton ( when g = 10m/s^2)
or
= 2.26 Newton (when g = 9.8 m/s^2)

or 0.231 gram ( when divided by g)