A steel cylinder has an aluminum alloy piston and at a temperature of 200C when the internal diameter of the cylinder is exactly 10 cm, there is an all-round clearance of 0.05 mm between the piston and the cylinder wall. At what temperature will the fit be perfect?
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Answer:
Total clearance =0.05mm×2=0.1mm
d(α
2
−α
1
)ΔT=0.1mm=0.01cm
10(0.4×10
−5
)ΔT=0.01 or ΔT=250
or T=250+20=270
o
C
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