A steel plug has a diameter of 5cm at 30°C. At what temperature will it fit exactly into a hole of constant diameter 4.997cm(coefficient of linear expansion of steel is 11×10^-6°C^-1)
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Explanation:
ΔL = L₀αΔT
ΔT = ΔL/(L₀α) (equation 1)
ΔL = 5 - 4.997 = 0.003 cm
L₀ = 5cm
α = whatever value you are given (depends on type of steel)
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