Question

a steel pulley was made from two big equal cylinders of diameter 10cm each and length 7cm,stuck at the ends of a small cylinder of diameter 7cm and lenght 3.5cm. Find the weight of the pulley if cm³ of steel weighs 7.6 grams.

Answer 1

Hope u like my process
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Diameter of big cylinder (D) =10 cm

Radius of big cylinder (R) =D/2= 5 cm

Length of big cylinder (H) = 7cm

Volume of a big cylinder(V)
$= \pi {r}^{2} h \\ = \frac{22}{7} \times {5}^{2} \times 7 \\ = 550 \: cm ^{3}$

Since there are two big cylinders so..

Total volume of big cylinders = 2×550
=1100cm³

Diameter of small cylinder (d) = 7cm

Radius of small cylinder (r) =d/2=3.5 cm

Length of small cylinder (h) =3.5cm

Volume of small cylinder(v)

$= \pi {r}^{2} h \\ = \frac{22}{7} \times {3.5}^{2} \times 3.5 \\ = 11 \times {3.5}^{2} \\ = 134.75 \: \: cm ^{3}$

So.
Total volume of pulley =V +v

= 1100 + 134.75 cm³

=1234.75 cm³

If 1 cm³ of pulley weighs 7.6 gm, then,

1234.75 cm³ weighs = 7.6× 1234.75 gm

= 9384.1 gm = 9 kg 384 g __(answer) __

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Answer 2

Answer:

here's the answer that

Step-by-step explanation:

Diameter of big cylinder (D) =10 cm

Radius of big cylinder (R) =D/2= 5 cm

Length of big cylinder (H) = 7cm

Volume of a big cylinder(V)

Since there are two big cylinders so..

Total volume of big cylinders = 2×550

=1100cm³

Diameter of small cylinder (d) = 7cm

Radius of small cylinder (r) =d/2=3.5 cm

Length of small cylinder (h) =3.5cm

Volume of small cylinder(v)

So.

Total volume of pulley =V +v

= 1100 + 134.75 cm³

=1234.75 cm³

If 1 cm³ of pulley weighs 7.6 gm, then,

1234.75 cm³ weighs = 7.6× 1234.75 gm

= 9384.1 gm = 9 kg 384 g

HOPE MY ANSWER WOULD HELP YOU !!!!