Physics, asked by jerushasonari, 1 day ago

A steel punch can be worked to compressive stress of 800 N/mm2 . Find diameter of hole which can be punched through a steel plate of 10 mm thick if ultimate shear stress of plate is 300 N/mm2.​

Answers

Answered by aryapriyanka892
1

Let d be the diameter of hole in mm Area being sheared = π.d.t = πd × 10 = 10πd mm2 Force required to punch the hole = Ultimate shear strength x area sheared = 350 × 10πd = 3500πd N Cross sectional area of the hole = π/4d2 mm2Compressive stress on the punch σC = 3500πd/{π/4d2} = 14000/d But σC is limited to 800 N/mm2 and therefore 800 = 14000/d d = 17.5mm

Answered by jaimaheshwari88
0

Answer:

A steel punch can be worked to a compressive stress of 800 N/mm2. Find the least diameter of hole which can be punched through a steel plate 10 mm thick if its ultimate shear strength is 350 N/mm2.Read more on Sarthaks.com - https://www.sarthaks.com/514914/steel-punch-worked-compressive-stress-800-find-the-least-diameter-hole-which-can-punched

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