Question

a steel tank has a volume of 438 L and is filled with 0.885 kg of O2. calculate the pressure of O2 at 21 degree Celsius ​

Answer 1

Answer:

The pressure of the $O_{2}$ gas at $21\textdegree C$ measured is $1.54bar$.

Explanation:

Data given,

The volume of the steel tank, V = $438L$

The mass of $O_{2}$ gas = $0.885kg$ = $885g$

The temperature of the $O_{2}$ gas, T = $21\textdegree C$ = $( 273.15 + 21 )K$ = $294.15K$

The pressure of the $O_{2}$ gas, P =?

Now, we can find out the pressure of the gas by using the ideal gas equation:

• $PV =nRT$
• P = $\frac{nRT}{V}$       -------equation (1)

Here, R = Raydberg's constant = $0.08314L-bar/K-mol$

And n = The number of moles of $O_{2}$

Firstly, we have to find out the number of moles:

The molar mass of $O_{2}$ = $32g/mol$

• The number of moles of $O_{2}$, n = $\frac{Given mass}{Molar mass}$ = $\frac{885}{32}$ = $27.65mol$

After putting the values of n, R, T, and V in equation (1), we get:

• P = $\frac{27.65\times 0.08314\times 295.15 }{438}$
• P = $1.54bar$

Hence, the pressure, P, of the $O_{2}$ gas measured is $1.54bar$.