Physics, asked by jack6778, 11 months ago

A steel tape 1m long is correctly calibrated for a temperature of 27.0 °C. The length of a steel rod measured by this tape is found to be 63.0 cm on a hot day when the temperature is 45.0 °C. What is the actual length of the steel rod on that day? What is the length of the same steel rod on a day when the temperature is 27.0 °C? Coefficient of linear expansion of steel = 1.20 × 10–5 K–1.

Answers

Answered by Anonymous
6

Answer:

Length of the steel tape at temperature T = 27°C, l = 1 m = 100 cm

At temperature T1 = 45°C, the length of the steel rod, l1 = 63 cm

Coefficient of linear expansion of steel, α = 1.20 × 10–5 K–1

Let l2 be the actual length of the steel rod and l' be the length of the steel tape at 45°C.

l' = l + αl(T1 - T)

∴ l' = 100 + 1.20 × 10-5 × 100(45 - 27)

= 100.0216 cm

Hence, the actual length of the steel rod measured by the steel tape at 45°C can be calculated as:

l2 = (100.0216 / 100) × 63 = 63.0136 cm

Therefore, the actual length of the rod at 45.0°C is 63.0136 cm. Its length at 27.0°C is 63.0 cm.

Answered by dhayadon
0

Answer:

heyyy!

Explanation:

l = 1 m = 100 cm

At temperature T1 = 45°C, the length of the steel rod, l1 = 63 cm

Coefficient of linear expansion of steel, α = 1.20 × 10–5 K–1

Let l2 be the actual length of the steel rod and l' be the length of the steel tape at 45°C.

l' = l + αl(T1 - T)

∴ l' = 100 + 1.20 × 10-5 × 100(45 - 27)

= 100.0216 cm

l2 = (100.0216 / 100) × 63 = 63.0136 cm

wid luv

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