Question

A steel tape 30m long at a temperature of 65ºF when lying horizontally

on the ground. Its sectional area is 0.082 cm2, its weight 2 kg and the co efficient of expansion 65 x10-7 per 1º F. the tape is stretched over three equal spans. Calculate the tape corrections under the following conditions at field, temperature = 85ºF, pull = 18kg, E= 2.109x106 kg/cm2​

Answer 1

Answer:

perceptional Kaleb Kayleigh McClain

Answer 2

Step-by-step explanation:

Ct = coefficient of expectation ( Tm- To) × L

= 65×10‐⁷×(85-65)×30

=3.9×10‐³m

Cp= (P-Po)L/AE

= (18-2)30/.082×2.109×10⁶

=2.77×10‐³ m

Total correction =(3.9+2.77)×10-³

=6.67×10-³m