Question

A steel wheel of 600 mm diameter rolls on a horizontal steel rail. it carries a load of 500 n. the coefficient of rolling resistance is 0.3 mm. the force in n, necessary to roll the wheel along the rail is (a) 0.5 (b) 5 (c) 15 (d) 150

Answer 1

Option(D) - 150.

Force F = 0.3 * 500

              = 150N.

Answer 2

Answer:

Option a - 0.5 N

Step-by-step explanation:

Given : A steel wheel of 600 mm diameter rolls on a horizontal steel rail. it carries a load of 500 n. The coefficient of rolling resistance is 0.3 mm.

To find : The force in n, necessary to roll the wheel along the rail is?

Solution :

The diameter of the wheel is 600 mm

Radius of the wheel is 300 mm

The formula to find the frictional force is

$F_r=\frac{W\times \mu_r}{R}$

Where, $F_r$ is the frictional force

W=500 N is the load on the wheel

$\mu_r=0.3 mm$

R=300 mm

Substitute the value in the formula,

$F_r=\frac{500\times 0.3}{300}$

$F_r=0.5$

Therefore, Option a is correct.

The frictional force is 0.5 N.