A steel wheel of 600mm diameter on a horizontal steel rail. It carries a load of 500n. The coefficient of rolling resistance is 0.3. The force in newton necessary to roll the wheel along the rail is
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Answer:
0.5.
Explanation:
From the question we get that the wheel is of diameter 600mm which is of radius 300mm that is attached on a horizontal steel rail. so, the formulae of the force will be given as F = W*μr/ R. Where W is the load which is sustained on wheel and the μr is the resistance coefficient of rolling and the R is radius of wheel .
So, on substituting the values from the question we will get that F = 500*0.3/300 = 0.5.
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