Question

a steel wire has length of 1m and area of cross section 1mm^2 the work required to increase it's lenght as Y=2×10^11 N/m^2​

Answer 1

Answer:

HOPE IT HELPS. !!!!.

Explanation:

Young's modulus, Y=

A

F

×lx

⇒ F=

l

YAx

Work done=

2

1

F×x=

2

1

l

YAx

2

=

2×1

2×10

11

×10

−6

×(2×10

−3

)

2

=0.4J