Question

A steel wire having a radius of 2.0 mm, carrying a load of 4 kg, is hanging from a ceiling. Given that g = 3.1π ms⁻² , what will be the tensile stress that would be developed in the wire?
(A) 6.2 × 10⁶ Nm⁻²
(B) 4.8 × 10⁶ Nm⁻²

(C) 5.2 × 10⁶ Nm⁻²
(D) 3.1 × 10⁶ Nm⁻²

Answer 1

Answer:

Option (D) 3.1 × 10⁶ Nm⁻²

Explanation:

Tensile stress in wire will be

=  Cross section Area  / Tensile force

= 4 * 3.1 π​ / π * 4 * 10^-6

HOPE THAT IT WAS HELPFUL!!!!

MARK IT THE BRAINLIEST IF IT REALLY WAS!!!!