Question

A steel wire having a radius of 2.0 mm, volume carrying a load of 4 kg, is hanging from a ceiling. Given that g=3.1 ms 2, what will be the tensile stress that would be developed in the wire?

Answer 1

Explanation:

Given A steel wire having a radius of 2.0 mm, volume carrying a load of 4 kg, is hanging from a ceiling. Given that g=3.1 ms 2, what will be the tensile stress that would be developed in the wire?

• T = F = 4 x 3.1 π N
• Tensile stress in wire will be Tensile force / cross section area
•                                           = mg / πR^2
•                                          = 4 x 3.1 π / π x (2 x 10^-3)^2
•                                        = 4 x 3.1 / 4 x 10^- 6
•                                          = 3.1 x 10^6 Nm^-2
• OR
• A = π r^2
•   = π (2 x 10^-3)^2
• So A = 4π x 10^-6 m^2
• We know that stress = F / A
•                                   = 4 x 3.1 π / 4 π x 10^-6
•                                  = 3.1 x 10^6 N / m^2

So stress will be 3.1 x 10^6 N / m^2

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