Question

A steel wire having cross sectional area 1.2mm2 is stretched by a force of 120N. If a lateral strain of 1.455mm is produced in the wire, calculate the Poisson's ratio.

Answer 1

Answer:

Solution A Steel Wire Having Cross Sectional Area 1.5 Mm2 When Stretched by ... Calculate the Mass Attached to the Wire. ... Poisson's ratio, σ =`"Lateral strain"/"Longitudinal.

Answer 2

The Poisson's ratio is 2.91.

Explanation:

Given that,

Area = 1.2 mm²

Force = 120 N

Lateral strain = 1.455 mm

We know the young modulus for steel

$Y=2\times10^{11}\ N/m^2$

We need to calculate the longitudinal stress

Using formula of longitudinal stress

$longitudinal\ stress =\dfrac{F}{A}$

Put the value into the formula

$longitudinal\ stress =\dfrac{120}{1.2\times10^{-6}}$

$longitudinal\ stress=10^8\ N/m^2$

We need to calculate the longitudinal strain

Using longitudinal strain

$longitudinal\ strain=\dfrac{longitudinal\ stress}{young\ modulus}$

Put the value into the formula

$longitudinal\ strain=\dfrac{10^8}{2\times10^{11}}$

$longitudinal\ strain=0.0005=5\times10^{-4}$

We need to calculate the Poisson's ratio

Using formula of Poisson's ratio

$\delta=\dfrac{lateral\ strain}{longitudinal\ strain}$

Put the value into the formula

$\delta=\dfrac{1.455\times10^{-3}}{5\times10^{-4}}$

$\delta=2.91$

Hence, The Poisson's ratio is 2.91.

#Learn more

Topic : Poisson's ratio

https://brainly.in/question/10616257

https://brainly.in/question/3209980