Question

a steel wire of diameter 1×10-³ m is stretched by a force of 20N. calculate the strain energy per unit valume (y steel = 2×10¹¹ N/m²)​

Answer 1

The strain energy stored per unit volume is Uo = 1623 J

Explanation:

Uo = (stress)^2/2 x Y

Stress = Force /area = 20 / π x ( 0.5 x 10^-3 )^2

Stress = 25.48 x 10^6 N/m^3

Uo = (25.48 x 10^6)^2 / 2 x 2 x 10^11

Uo = 1623 J

Thus the strain energy stored per unit volume is Uo = 1623 J

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