Question

A steel wire of length 1m, mass 0.1kg and uniform cross-sectional area 10^(-6)m^(2) is rigidly fixed at both ends. The temperature of the wire is lowered by 20^(@)C. If transverse calculate the frequency of the fundamental mode of vibration. Given for steel Y = 2 xx 10^(11)N//m^(2) alpha = 1.21 xx 10^(-5) per ^(@)C

Answer 1

Change in length dl of the wire when the temperature is lowered by 20°C is

Answer 2

Answer:

Hey Buddy here's ur answer