A steel wire of length 2.3m stretched by a load of 5kg, produces an extensionof
0.03x10 m. Calculate the young's modulus of the material. Diameter of the wire is
1.5x10-3m.
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Answer:
Y=2.16x10^8 Pa
Explanation:
L=2.3 ; F=mg=5kg*10m/s^2=50N ; ΔL=0.3m ; d=1.5*10^-3 ; r=1.5x10^-3/2
so, Y=(F/A)/(ΔL/L)
= (50*πr^2)/(0.3/2.3)
= 3220/14.85x10^6
= 216.83x10^6
= 2.16x10^8 Pa <-answer
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