Physics, asked by BrainlyHelper, 1 year ago

A steel wire of length 4.7 m and cross-sectional area 3.0 × 10-5 m2 stretches by the same amount as a copper wire of length 3.5 m and cross-sectional area of 4.0 × 10–5 m2 under a given load. What is the ratio of the Young’s modulus of steel to that of copper Question 9.1 machenical properties of the solid

Answers

Answered by Anonymous
99
The ratio of Young's modulus of steel to that of copper is 1.79:1


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Answered by Anonymous
42
Young's modulus for steel wire 

Y1 = (F1/A1) x (L1/ΔL1) 

= F1 x 4.7 / 3.0 x 10⁻⁵ x ΔL ----(1) 

Young's modulus for copper 

Y2 = (F2/A2) x (L2 /ΔL2) 

     = F x 3.5 / 4 x 10^-5 x ΔL----(2) 

By 1 and 2 

Y1 / Y2 = 4.7 x 4.0 x 10^-5 / 3.0 x 10^-5 x 3.5 = 1.79 : 1 
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