A Steel wire of length 4.7 m and cross sectional area 3.0 × 10⁻⁵ m² stretches by the same amount as a copper wire of length 3.5 m and cross-sectional area of 4.0 × 10⁻⁵ m² under a given load. What is the ratio of the Young's modulus of Steel to that of Copper?
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◆ Answer -
Ys/Yc = 1.79
◆ Explanation-
# Given-
Ls = 4.7 m
As = 3×10^-5 m^2
Lc = 3.5 m
Ac = 4×10^/5 m^2
# Solution-
We know that,
Y = FL / A∆L
But here, F & ∆L are constant.
Therefore,
Ys/Yc = LsAc / AsLc
Ys/Yc = (4.7×4×10^-5) / (3.5×3×10^-5)
Ys/Yc = 1.79
Hence, we can say that Ys/Yc = 1.79 .
Hope that is useful...
◆ Answer -
Ys/Yc = 1.79
◆ Explanation-
# Given-
Ls = 4.7 m
As = 3×10^-5 m^2
Lc = 3.5 m
Ac = 4×10^/5 m^2
# Solution-
We know that,
Y = FL / A∆L
But here, F & ∆L are constant.
Therefore,
Ys/Yc = LsAc / AsLc
Ys/Yc = (4.7×4×10^-5) / (3.5×3×10^-5)
Ys/Yc = 1.79
Hence, we can say that Ys/Yc = 1.79 .
Hope that is useful...
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