Question

A Steel Wire of length 4m & diameter 5mm is stretched by 5kg wt.Find the increase in length if y of of steel is 2*10 11 Nm -2

(g=9.8m/s)

Answer 1

The increase in length of the wire is 0.00005 m

Explanation:

Given data:

Force "F" = 5 Kg wt

                = 5 x 9.8 = 49 N

• Area of cross section of the wire is

A = πd^2 / 4

A = 3.14 x (5 x 10^-3)62 / 4

A = 1.9625 x 10^-5 m^2

Now

Young's modulus "Y" = F/A ÷ Δl / l

Δl = Fl / AY

    = 49 x 4 / 1.9625 x 10^-5 x 2 x 10^11

    = 0.00005 m

Thus the increase in length of the wire is 0.00005 m

Also length more

Find the Resistivity.  If the length of the wire is 50 cm and the radius is 0.5 mm, find the resistivity of wire if its resistance is 30 ohms. ?

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