Question

A steel wire of length ???? has a magnetic moment M. It is then
bent into a semicircular arc. The new magnetic moment is
(a) M/π (b) 2M/π (c) 3M/π (d) 4M/π

Answer 1

Length L, long wire is twisted in the state of half circle of span r. at that point, length of wire = circuit of half circle L = πr

=> r = L/2π now, attractive dipole = attractive dipole minute × least detachment between two dipoles here obviously, least division between dipoles is 2r = 2L/π consequently, attractive dipole = M × 2L/π = 2ML/π.

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