Question

A steel wire of radius 0.05 cm is stretched
with a load of 3 kg. Calculate the length of the
wire which will be in resonance with a tuning
fork of frequency 340 Hz. Density of steel is
8 g/cm".​

Answer 1

Answer:

Length of the wire is 10 cm

Explanation:

As we know that the speed of the wave in the wire is given as

$v = \sqrt{\frac{T}{\rho \pi r^2}}$

now we know that

r = 0.05 cm

$T = mg$

$T = 3\times 9.8$

$\rho = 8000 kg/m^3$

now we have

$v = \sqrt{\frac{3(9.8)}{(8000)\pi(0.0005)^2}}$

$v = 68.4 m/s$

now we have

$f = \frac{v}{2L}$

$340 = \frac{68.4}{2L}$

$L = 10 cm$

#Learn

Topic : Waves in string

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