a steel wire tied to the top of an electric pole is a fixed at a point on the ground at a distance of 6 m from the foot of the pole if the wire makes an angle of elevation of 60 degree find the length of the wire
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Given :
OA = 10 m ( electric pole)
∠B = 45°
Let OA be the electric Pole and B be the point on the ground.
Let BA = x cm
In ∆ABO
sin 45° = AO /AB (perpendicular/ hypotenuse)
1 / √ 2 = 10 / x
x = 10 √2
x = 10 × 1.414 (Given √2 = 1.414)
x = 14.14 m
Hence, length of the wire is 14.14 m.
HOPE THIS WILL HELP ..........
swarup33:
hey the angle of elevation is 60 degree
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the length of the wire is 12 cm
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