Question

a steel wire when bent in the form of a square encloses an area of 196 sq . cm . if the same wire is bent into the form of a circle, find the area of the circle. (use pi = 22/7 )

Answer 1

area of square =196
side × side =196
(side)^2 =196
side = 14cm
perimeter = 4 × side
= 4×14
= 56cm
perimeter of square = perimeter of circle 56 = 2piR
56 = 2 × 22/7 R
56×7/44 = R
now with help of R u can find area
mark it as brainlist plz.....

Answer 2

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$\large \boxed{ \textsf{given:-}}$

$\texttt {\: enclosed area of steel wire when bent to form square = 196 \: sq.cm }$

$\large \boxed{ \textsf{to find out:-}}$

$\textsf{the area of circle}=??$

$\large \boxed{ \rm \: solution:-}$

$\rm \: Side \: a \: square \: = \sqrt{196}cm = 14cm$

$\rm \: perimeter \: of \: square = (4 \times 14)cm = 56cm$

$\rm \therefore \: length \: of \: the \: wire \: = 56cm$

$\rm \therefore \: circumference \: of \: the \: circle \: = length \: of \: wire = 56cm$

$\textsf{let the radius of the circle be }r \rm \: cm$

$\rm \: then \: 2 \pi \: r = 56 \implies \: 2 \times \large \frac{22}{7} \small r = 56 \implies \: r =7.31$

$\rm \therefore \: area \: of \: the \: circle = \pi \: r {}^{2}$

$\large \rm \: = \huge( \small \frac{22}{7} \times 7.31 \times 7.31\huge) \small \:cm {}^{2} = 167.94 \: cm {}^{2}$