Question

A step index fiber has a core with a refractive index of 1.50 and a cladding with a refractive index of 1.46. Its numerical aperture is

Answer 1

Answer:

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Answer 2

Answer:

Here,μ

1

=1.50;μ

2

=1.47;

μ

0

=1

(i) Critical angle θ

c

at the core-cladding interface is given by

θ

c

=sin

−1

1.50

1.47

=78.5

0

(ii) Numerical aperture,NA=(μ

1

2

−μ

2

2

)

2

1

=[(1.50)

2

−(1.47)

2

]

2

1

=(2.25−2.16)

1/2

=0.30

(iii) Acceptance angle θ

a

=sin

−1

(NA)

=sin

−1

(0.30)=17.4

0

Explanation:

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