A step index fiber is made with a core of refractive index 1.52, a diameter of 49µm and a fractional refractive index change of 0.0007.It is operated at a wavelength of 1.3µm. Find the normalized frequency of the fiber.
Answers
Answered by
0
Answer:
An optical fiber has an index of refraction n and diameter d. It is surrounded by vacuum. Light is sent into the fiber along its axis as shown in Figure P25.36. (a) Find the smallest outside radius Rmin permitted for a bend in the fiber if no light is to escape. (b) What If? What result does part (a) predict as d approaches zero? Is this behavior reasonable? Explain. (c) As n increases? (d) As n approaches 1?(e) Evaluate Rmin assuming the fiber diameter is 100μm and its index of refraction is 1.40
Explanation:
Answered by
0
Answer:
Explanation:
good
Similar questions