Question

A step-up transformer operates on a 230 V line and supplies current of 2 A to a load.The ratio of the primary and secondary windings is 1:25. The current in the primary coil is​

Answer 1

Answer:

see this attachment hope it's helpful

Answer 2

=> ip = 50 A

Explanation

As change in flux of primary and secondary coil is proportional to the no. of turns in primary and secondary coil respectively.

So, Φ/Np = Φ/Ns

or, 1/Np × dΦ/dt = 1/Ns dΦ / dt

Vs /Vp = Ns/Np _[as V ∝ dΦ/dt ]

For no loss of power,

Vi = constant

i =1/V × constant

ip /is =Vs/Vp

ip /is = Ns/Np

[ ip and is are currents in primary and secondary coils ]

Here, Np/Ns = 1/25

is= 2A

ip/2 = 25/1

or ip = 25 × 2 = 50A

The current in the primary coil is 50A !

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