Question

A stick of mass m and length l is pivoted at one end and is displaced through an angle θ. The increase in potential energy is 

Answer 1

ans is mgl/2(1-costheta)

bez P.Einitail=mgl/2 h=l/2

P.E final=mgl/2 cos theta P. E is in cos direction

so P.Ef- P.Ei= mgl/2(1-cos theta)

hope it help

Answer 2

ans is mgl/2(1-costheta)

bez P.Einitail=mgl/2 h=l/2

P.E final=mgl/2 cos theta P. E is in cos direction

so P.Ef- P.Ei= mgl/2(1-cos theta)

hope it help

Answer 3

ans is mgl/2(1-costheta)

bez P.Einitail=mgl/2 h=l/2

P.E final=mgl/2 cos theta P. E is in cos direction

so P.Ef- P.Ei= mgl/2(1-cos theta)

hope it help

Answer 4

ans is mgl/2(1-costheta)

bez P.Einitail=mgl/2 h=l/2

P.E final=mgl/2 cos theta P. E is in cos direction

so P.Ef- P.Ei= mgl/2(1-cos theta)

hope it help