Question

a stock solution is 2.5 M . K2Cr207, how many cm3 of this solution you would need to dilute to make 50 cm3 of 0.05 M solution?​

Answer 1

Answer:

1 $cm^{3}$

Explanation:

C1V1=C2V2

2.5*V1=0.05*50

V1= 0.05*50/2.5= 1 $cm^{3}$