Question

a ston dropped from top of a tower of hight 280 m high, splashes into the water of pond near the base of tower. when is the splash heard at the top given that the speed of sound in air is 340ms^-1 ? (g=9.8ms^-1)​

Answer 1

Answer:

Explanation:

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Answer 2

Answer:

The sound of a splash was heard at the top of a tower after 8.37sec.

Explanation:

Initial speed of stone = 0m/sec.

The time is taken by the stone from the top of a tower to the tower's base  $t_{1}$.

By the equation,

$S=ut_{1} +\frac{1}{2}at_{1} ^{2}$

280=0×$t_{1} +\frac{1}{2}9.8t_{1} ^{2}$

$t_{1}=7.55sec$

The sound of a splash was heard at the top of a tower after $t_{2} sec$ when the stone splashed into the water of the pond.

By the equation,

$t_{2}=\frac{S}{V}$

   = 280/340

   = 0.82sec

Total time$=t_{1} +t_{2}$

                = 7.55+0.82

                = 8.37sec

So, the sound of a splash was heard at the top of a tower after 8.37sec.