Physics, asked by himalirr, 1 year ago

A stone A is dropped from rest from a heighth above the ground. A second stone B is simultaneously thrown
vertically up from a point on the ground with velocity v The line of motion of both the stones is same. The value
of v which would enable the stone B to meet the stone A midway (at mid point) between their initial positions is
(A) 2 gh
(B) 2root gh
(C) root gh
(D)root 2gh
3.
A ball thrown up in vacuum returns after 12 sec. Its position after five seconds will be same as after:
(A) 7 sec
(B) 3 sec
(C) 4 sec
(D) 3.5 sec

Answers

Answered by vaidik04
0

Answer:

Hi mate

the answer is here

3. (B) 3sec

Thanks

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