A stone accelerates from rest uniformly at 10 m/s² when it is dropped down a deep well. It hits the water at the bottom of the well after 5 s. Calculate how fast it is travelling when it hits the water.
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Answer:
50 m/s
Step-by-step explanation:
v = u + at
u = 0 (given that its dropped)
v = at
v = 10(5)
v = 50m/s
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