Question

A stone accelerates from rest uniformly at 10 m/s² when it is dropped down a deep well. It hits the water at the bottom of the well after 5 s. Calculate how fast it is travelling when it hits the water.
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Answer 1

Answer:

Given, acceleration of stone is a=g=9.8m/s

2

Initial velocity is u=0m/s

Time for hitting water is t=3.41s

If d be the depth of the well.

Using d=ut+at

2

/2,

∴ d=0(3.41)+0.5(9.8)(3.41)

2

=56.98∼57m